 # Python Program to Count the Number of Digits Present In a Number

In this example, you will learn to count the number of digits present in a number.

To understand this example, you should have the knowledge of the following Python programming topics:

## Example 1: Count Number of Digits in an Integer using while loop

``````num = 3452
count = 0

while num != 0:
num //= 10
count += 1

print("Number of digits: " + str(count))``````

Output

`Number of digits: 4`

In this program, the while loop is iterated until the test expression `num != 0` is evaluated to 0 (false).

1. After the first iteration, `num` will be divided by 10 and its value will be 345. Then, the `count` is incremented to 1.
2. After the second iteration, the value of `num` will be 34 and the `count` is incremented to 2.
3. After the third iteration, the value of `num` will be 3 and the `count` is incremented to 3.
4. After the fourth iteration, the value of `num` will be 0 and the `count` is incremented to 4.
5. Then the test expression is evaluated to false and the loop terminates.

## Example 2: Using inbuilt methods

``````num = 123456
print(len(str(num)))``````

Output

`6`

In the above example, we first convert the integer value into string by using `str()`. Then, we find the length of the string using `len()`.